**Practice** Problems

Use the theorem above to find the measure of angle formed by the intersection of the tangent that intersects chord AC.

By the theorem, the measure of angle is half of the intercepted arc which is 170°.

Therefore $$ x = \frac{1}{2} \cdot 170 = 85^{\circ} $$

Total measure of circle's circumference = 360°

$$ \frac 3 4 (360^{\circ}) = 270^{\circ} $$

By our theorem, we know that the angle formed by a tangent and a chord must equal half of the intercepted arc so $$x = \frac 1 2 \cdot 360^{\circ} =270^{\circ} $$

Circle 1 is the only circle whose intercepted arc is half the measure of the angle between the chord and the intersecting line.

The key to this problem is recognizing that $$ \overline{AOC}$$ is a diameter .

Therefore, $$m \overparen{ABC} = 180 ^{\circ} $$

At this point, you can use the formula, $$ \\ m \angle ACZ= \frac{1}{2} \cdot 180 ^{\circ} \\ m \angle ACZ= 90 ^{\circ} $$

The key to this problem is recognizing that the total degrees in a circle is $$ 360^{\circ} $$

From there you can set up an equation using the 3: 2 ratio.

$$ 3x + 2x =360 \\ 5x = 360 \\ \frac{5x}{5} = \frac{360}{5} \\ x = 72 \\ \overparen {JLM }= 2x = 2 \cdot 72 \\ \overparen {JLM }=144 ^{\circ} $$

At this point, you can use the formula, $$ \\ m \angle MJK= \frac{1}{2} \cdot 144 ^{\circ} \\ m \angle MJK = 72 ^{\circ} $$

Free Math Printable Worksheets: Circles Worksheets and Activites for Math Teachers