### Practice Problems

##### Problem 1

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##### Problem 2

CA and YW are corresponding.

Follow the letters: $$ \triangle \red A B \red C$$ ~ $$\triangle \red W X \red Y$$

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##### Problem 3

Step 1) Pick a pair of corresponding sides (follow the letters) |
AB and AD are corresponding based on the letters of the triangle names
$$ \triangle \color{red}{AB}C$$ ~ $$\triangle \color{red}{AD}E$$ |

Step 2) Substitute side lengths into proportion |
$$ \frac{AB}{AD} = \frac{40}{30} $$ |

Step 3) Simplify (if necessary) |
$$ \frac{40}{30}=\frac{4}{3} $$ |

##### Problem 4

Since AX and AC are corresponding, just set up a proportion and solve:

$ \frac{2}{5} = \frac{x}{10} \\ \frac{2 \cdot 10}{5} = x \\ x = 4 $

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##### Problem 5

Two triangles are similar, and the ratio of each pair of corresponding sides is 4 : 3 . Which statement regarding the two triangles is true?

##### Problem 6

Two triangles are similar, and the ratio of each pair of corresponding sides is 2 : 5. Which statement regarding the two triangles is true?

##### Problem 7

$ \frac{P}{G} = \frac{H}{b} \\ \frac{4}{12} = \frac{3}{b} \\ 4 \cdot b = 36 \\ b= 9 $

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##### Problem 8

No, because the ratios of the sides are not proportional

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##### Problem 9

No, because the ratios of the sides are not proportional.

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