Example of 2 triangles satisfying the law of sines formula
Consider the following problem. A triangle has side lengths of 20 and 11. The angle opposite the latter side is 29° . What is the measure of the angle opposite of the side that has a length of 20? See the picture immediately below.
ie Do the two angles that you currently have a sum that is less than 180
Check if there is a second angle that is valid. To do this, find the angle in Quadrant II that has the same sine as the angle that you found in Step 2 (subtract that angle from 180)
If the angle in Quadrant II plus the original angle you were given have a sum that is less than 180, you have a second triangle that works.
Try the interactive demonstration below to better understand how to use these steps to solve the ambiguous case of the law of sines