Side Splitter Theorem

A theorem to find sides of similar triangles

What is the side splitter theorem?

Answer: The side splitter theorem states that if a line is parallel to a side of a triangle and intersect the other two sides, then this line divides those two sides proportionally.

The side splitter theorem is a natural extension of similarity ratio, and it happens any time that a pair of parallel lines intersect a triangle.

Example Side Splitter Theorem Picture

The Side Splitter theorem states that
$ \frac{AC}{CE} = \frac{AB}{BD} $

Is the proportion below true?

formula non example
$ \frac{LP}{PO} = \frac{LM}{MN} $

No, this example is not accurate. PM is obviously not parallel to OM

Therefore, the side splitter theorem does not hold and is not true.

$ \frac{LP}{PO} \color{Red}{\ne} \frac{LM}{MN} $

Is the proportion below true?

$ \frac{VW}{WY} = \frac{WX}{YZ} $

No, remember this theorem only applies to the segments that are 'split' or intercepted by the parallel lines.

$ \frac{VW}{WY} \color{Red}{\ne} \frac{WX}{YZ} $

Instead, you could set up the following proportion:

$ \frac{VW}{WY} = \frac{VX}{XZ} $

What if there are more than two parallel lines?

Answer: A corollary of the this theorem is that when three parallel lines intersect two transversals, then the segments intercepted on the transversal are proportional.

Example 1 corollary to side splitter theorem example, picture Example 2 Side Splitter full

Practice Problems

Problem 1

Find the length of VX by using the side splitter theorem.

Practice Problem side splitter theorem

To solve this problem, set up the following proportion and solve:
$$ \frac{VW}{WY} = \frac{VX}{XZ} \\ \frac{7}{14} = \frac{VX}{16} \\ \frac{16 \cdot 7}{14} = VX \\ VX = 8 $$

Problem 2

Use the corollary to find the value of x in the problem pictured below.

problem on corollary to side splitter theorem

Set up the proportion then solve for x:

Problem 3

Use the corollary to find the value of x in the problem pictured below.

problem on corollary to side splitter theorem
Problem 4

Are the red segments pictured below parallel? (Picture not to scale)

problem 4

If the red segments are parallel, then they 'split' or divide triangle's sides proportionally. However, when you try to set up the proportion, you will se that it is not true:
$ \frac{10}{12} \color{Red}{\ne} \frac{8}{14} $

Therefore, the red segments are not parallel

back to Similar Triangles Next to Angle Bisector Theorem